There are 4 boys and 3 girls. wht is probability that boys and girls sit alternately in row
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=5! * 3!
So, required probability= P(E) = cardinality(E)/cardinality(S) = (5!*3!)/7! = 1/7
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= 5! * 3!
So, Required probabilty = P (E) cardinately (E)/ cardinately (S) = (5! * 3!)/ 7!
= 1/7.
So, Required probabilty = P (E) cardinately (E)/ cardinately (S) = (5! * 3!)/ 7!
= 1/7.
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