Question

there are 4 boys and 5 girls in two separate queues. the two queues are merged so that the positions of the boys (in relation to each other) and those of the girls (in relation to each other) remain unchanged. in how many ways can this be done?

Answer 1

Your answer mate ^_^

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Number of boys = 4

Number of girls = 5

Total number = 4 + 5 = 9

Number of permutations = 9! = 362 , 880

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Answer 2

Hello friend here is your answer


Number of boys = 4
Number of girls = 5
Total number = 4 + 5 = 9
Number of permutations = 91
= 362 , 880


Hope this will help