Question

There are 4 boys and 5 girls in two separate queues. The two queues are merged so that the positions of the boys (in relation to each other) and those of the girls (in relation to each other) remain unchanged. In how many ways can this be done?
option
a) 5!4!
b) 9P5
c) 9C5
d) (9C5 )^2; There are 4 boys and 5 girls in two separate queues. The two queues are merged so that the positions of the boys (in relation to each other) and those of the girls (in relation to each other) remain unchanged. In how many ways can this be done?; option; a) 5!4!; b) 9P5; c) 9C5; d) (9C5 )^2

Answer 1

4 boys and 5 girls can be arranged in this way. 
G1 B1 G2 B2 G3 B3 G4 B4 G5

SO total ways 5!4! (answer)

$<b>hope it helps$ ❣️✌️