Math, asked by jvpalmadiaz7560, 1 year ago

There are 4 copies of 5 different books in how many ways can they be arranged on a shelf

Answers

Answered by shadowsabers03
13

   

Let each different book be indicated as A, B, C, D and E.

Each book has 4 copies. So, one such arrangement is given below.

AAAABBBBCCCCDDDDEEEE

Here, we got a 20-letter word of 5 letters recurring 4 times each.

Now I'm changing the question as the following:

"How many meaningful and non-meaningful words can be formed by rearranging the letters in the word AAAABBBBCCCCDDDDEEEE?"

Here, the answer is,

\ \ \ \ \ \boxed{\frac{20!}{4! \times 4! \times 4! \times 4! \times 4!}} \\ \\ \\ \Rightarrow\ \boxed{\frac{20 \times 19 \times 18 \times 17 \times 16 \times 15 \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5}{4 \times 3 \times 2 \times 4 \times 3 \times 2 \times 4 \times 3 \times 2 \times 4 \times 3 \times 2}}

\Rightarrow\ \boxed{5 \times 19 \times 18 \times 17 \times 15 \times 14 \times 13 \times 11 \times 10 \times 7 \times 5} \\ \\ \\ \Rightarrow\ \boxed{\bold{3,05,54,02,35,000}}

Thus we can arrange 4 copies of 5 different books on a shelf in 3,05,54,02,35,000 ways.

Hope this helps you.

Plz mark it as the brainliest if this helps.

Plz ask me if you've any doubts on my answer.

The answer is on my own words and not from any source.

Thank you. :-))

           

Similar questions