There are 4 hotels in a certain city. If 3 men check into hotels in a day, find the probability that 2 men check into a same hotel
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Solution(By Examveda Team)
Cases, when 3 men are checking in different hotels = 4 × 3 × 2 = 24 ways.
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Total number of ways of checking in the 4 hotels by 3 men = 4 × 4 × 4 = 43. Number of ways in which each man checks into a different hotel = 4 × 3 × 2 (As for the 1st person, there are 4 choices, for 2nd remaining 3, and for the 3rd remaining 2). ∴ P(Each person checks into a different hotel) = 4 × 3 × 2 4 × 4 × 4 4×3×24×4×4 = 3 8 38
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