Question

There are 4 numbers. The H.C.F. of each pair is 3 and the L.C.M. of all the 4 numbers is 116. What is the product of 4 numbers?
(a) 9782
(b) 9396
(C) 9224
(d) 9100
PLEASE ANSWER STEP BY STEP​ SO I CAN UNDERSTAND. DON'T JUST ANSWER DIRECTLY ​

Answer 1

Answer:

abhindmalpotra5

abhindmalpotra5

2 hours ago

Math

Secondary School

+5 pts

Answered

There are 4 numbers. The H.C.F. of each

pair is 3 and the L.C.M. of all the 4 numbers is

116. What is the product of 4 numbers?

(a) 9782

(b) 9396

(C) 9224

(d) 9100

PLEASE ANSWER STEP BY STEP SO I CAN UNDERSTAND. DON'T JUST ANSWER DIRECTLY

1

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Answer:

Product=(b) 9396

Step-by-step explanation:

Please do correction in question as :

There are 4 numbers. The H.C.F. of each

pair is 3 and the L.C.M. of all the 4 numbers is

348.

******************************************************

As 3 is HCF of each pair is

So numbers are 3a,3b,3c,3d

LCM=3*abcd=348

abcd=348/3=116

Thus product of all 4 numbers

=3a*3b*3c*3d

=81abcd

=81*116

=9396