Question

There are 40 passengers in a bus, some with Rs. 3 tickets and remaining with Rs.10 tickets. The total collection from these passengers is Rs. 295. Find how many passengers have tickets worth Rs. 3?

Answer 1

Step-by-step explanation:

Let number of passengers having ticket worth Rs.3 be x

So, total cost of x tickets = 3x

Let number of passengers having ticket worth Rs.10 be y

So, total cost of y tickets = 10y

Since we are given that there are 40 passengers in bus.

So, x+y=40x+y=40   -1

We are also given that the total collection from these passengers is rs.295.

So, 3x+10y= 2953x+10y=295  --2

Substitute the value of x from 1 in 2

So,3(40-y)+10y= 2953(40−y)+10y=295  

120-3y+10y= 295120−3y+10y=295  

120+7y= 295120+7y=295  

7y= 1757y=175  

y= 25y=25  

Substitute the value of y in 1

x+25=40x+25=40

x=15x=15

So, 15 passengers  have tickets worth rs.3

Answer 2

Answer:

15 passengers.

Step-by-step explanation:

Let the number of passengers with ₹3 ticket be x number of passengers with ₹10 ticket be y

The total collection is: ₹295

Hence,

3x + 10y = 295 -----(1)

Also, the total number of passengers is 40.

Hence,

x + y = 40 -----(2)

3x + 10y = 295

x + y = 40

Let us multiply the equation (2) by 3 to eleminate x.

3x + 10y = 295

3x + 3y = 120

Solving the equations,

7y = 175

y = 25

Hence the number of passengers with ₹10 tickets is 25

Substitute y = 25 in (2)

i.e, x + y = 40

x = 40 - 25

x = 15