there are 40 passengers in a bus some with Rs.3 tickets and remaining with Rs.10 tickets. The total collections from then is Rs.267. Find how many passengers have tickets with Rs.3
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Answered by
0
Answer:
Let the number of passengers bought Rs. 3 tickets = x
Let the number of passengers bought Rs. 10 tickets = y
Given, there are 40 passengers in a bus
x + y = 40⋯(i)
Again, total collection from the passengers is Rs. 295
3x + 10y = 295⋯(ii)
substract (i) from (ii)
Multiply by 10 in (i)
10x + 10y = 400⋯(iii)
substract (iii) and (ii)
10x-3x + 10y-10y = 400-295
7x = 105
So, the number of passengers bought Rs.3 tickets is 15
Answered by
0
let the number of people with 3rs ticket - x
people with 10rs ticket-y
x+y=40 (given)
3x+10y= 267
using elim method
3x+3y=120
3x+10y=267
subracting them
7y= 267 -120
7y=147
y=21
x+y=40 (from above)
x+21=40
x=40-21
x=19
number of people with 3rs ticket = 19
thank you
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