Question

There are 40 passengers in a bus, some with Rs3 tickets remaining with Rs10 tickets. The total collection from these passengers is Rs295. Find how many passengers have tickets worth Rs3.

Answer 1

Answer:

Let the Passengers having Rs. 3 tickets be n and of Rs. 10 tickets be (40 – n).

☯ According to the Question :

⇢ (Rs. 3 + Rs. 10) Ticket = Rs. 295

⇢ (Rs. 3 × n) + (Rs. 10 × (40 – n)) = Rs. 295

⇢ Rs. 3n + Rs. 400 – Rs. 10n = Rs. 295

⇢ Rs. 400 – Rs. 295 = Rs. 10n – Rs. 3n

⇢ Rs. 105 = Rs. 7n

• Dividing both term by Rs. 7

⇢ n = 15 [ Rs. 3 Ticket Passengers ]

∴ There are 15 Rs. 3 tickets passengers.

━━━━━━━━━━━━━━━

☢ VERIFICATION :

⇴ (Rs. 3 + Rs. 10) Ticket = Rs. 295

⇴ (Rs. 3 × n) + (Rs. 10 × (40 – n)) = Rs. 295

⇴ Rs. 3n + Rs. 400 – Rs. 10n = Rs. 295

⇴ Rs. 400 – Rs. 7n = Rs. 295

⇴ Rs. 400 – Rs. 7(15) = Rs. 295

⇴ Rs. 400 – Rs. 105 = Rs. 295

⇴ Rs. 295 = Rs. 295 ⠀ ⠀Hence, Verified!

Answer 2

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$\huge\tt{GIVEN:}$

• There are 40 passengers in a bus, some with Rs3 tickets remaining with Rs10 tickets.
• The total collection from these passengers is Rs295.

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$\huge\tt{TO~FIND:}$

• How many passengers have tickets worth Rs3.

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$\huge\tt{SOLUTION:}$

Let x passangers have ticket worth ₹3 and (40-x )be the passengers having tickets worth ₹10

➩₹(3+10) Tickets = ₹295

➩₹(3×10) + (₹10×(40-x)) = ₹295

➩3x + ₹400 - 10x = ₹295

➩₹400 - ₹295 = 10x - 3x

➩105= 7x

➩15 = x

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There are 15 passangers having a ticket worth ₹3

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