Question

there are 40 passengers in bus ,some with rs.3 tickets and remaining with rs.10 tickets.the total collection from these passengers is rs.295. find how many passengers have tickets worth rs.3

Answer 1

3x  + 10(40-x)=295

Solving this you get x=15
So 15 people have taken the Rs. 3 tickets and the remaining 25 have taken the 10 Rupee ticket.
:)

Answer 2

Answer:

15 passengers

Step-by-step explanation:

Let number of passengers having ticket worth Rs.3 be x

So, total cost of x tickets = 3x

Let number of passengers having ticket worth Rs.10 be y

So, total cost of y tickets = 10y

Since we are given that there are 40 passengers in bus.

So, $x+y=40$   -1

We are also given that the total collection from these passengers is rs.295.

So, $3x+10y= 295$  --2

Substitute the value of x from 1 in 2

So,$3(40-y)+10y= 295$  

$120-3y+10y= 295$  

$120+7y= 295$  

$7y= 175$  

$y= 25$  

Substitute the value of y in 1

$x+25=40$

$x=15$

So, 15 passengers  have tickets worth rs.3