Math, asked by s154292, 1 day ago

There are 49 dogs signed up for a dog show. There are 36 more small dogs than large dogs. How many small dogs have signed up to compete?

Answers

Answered by rathod9999
1

Answer:

x = number large dogs

x + 36 = number small dogs

x + (x + 36) = 49

2x + 36 = 49

2x = 13

x = 6.5 large dogs

x + 36 = 42.5 small dogs

Since I highly doubt we have any "half dogs" the numbers given in the problem are off.

If there were an even number of total dogs this would work. As it is, we have either

6 large, 43 small or 7 large, 42 small ...

Neither case actually gives 36 more small dogs and a total of 49.

Answered by Anonymous
7

Answer:

Answer is 42.5

To figure out how many small dogs are competing, you have to subtract 36 from 49 and then divide that answer, 13 by 2, to get 6.5 dogs, or the number of big dogs competing. But you’re not done yet! You then have to add 6.5 to 36 to get the number of small dogs competing, which is 42.5. Of course, it’s not actually possible for half a dog to compete in a dog show, but for the sake of this math problem let’s assume that it is.

Similar questions