Question

There are 5 black and 6 red balls in a bag. How many selections can be made taking 2 black and 3 red balls
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Answer 1

Answer:200

Step-by-step explanation:

here, we will use combination as we have to do selection.

Number of selection of 2 black balls out of 5=C(5,2)=5!/2!3!=(5*4*3!)/(2*3!)=10

Number of selection of 3 red balls out of 6=C(6,3)=6!/3!3!=(6*5*4*3!)/(6*3!)=20

Total selection using product rule=10*20=200