There are 5 blue beds and 7 black beds in a box. if one bed is taken without looking.
A) What is the probability of getting a blue bed?
B)What is the probability of a black bed?
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No. of all possible outcomes = 5blue + 7black
n(S) = 13 beds
A) Let P(A) be the probability that the bed taken out was of blue colour.
> No. of outcomes favourable to A [n(a)] = 5
Therefore,
P(A) = n(a) / n(S) = 5 / 13
B) Let P(B) be the probability that the bed taken out was of black colour.
> No. of outcomes favourable to B [n(b)] = 7
Therefore,
P(A) = n(b) / n(S) = 7 / 13
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