Question

There are 5 boys and 4 girls.They sit in a row randomly.what are the chances that all the girls do not together​

Answer 1

Step-by-step explanation:

There are 4 boys and 4 girls. In how many ways can they be seated in a row so that all the girls do not sit together?

There are 4 boys and 4 girls. In how many ways can they be seated in a row so that all the girls do not sit together?There are 8 persons in total (4 boys + 4 girls)

There are 4 boys and 4 girls. In how many ways can they be seated in a row so that all the girls do not sit together?There are 8 persons in total (4 boys + 4 girls)So the number of ways in which 8 persons can be arranged is 8! ways.

There are 4 boys and 4 girls. In how many ways can they be seated in a row so that all the girls do not sit together?There are 8 persons in total (4 boys + 4 girls)So the number of ways in which 8 persons can be arranged is 8! ways.Let us consider the 4 girls as a single person so there are now 5 persons in total (4 boys + 4 girls as one group or one person). So the number of ways in which 5 persons can be arranged is 5! ways and also the 4 girls can sit among themselves in 4! way so the total number of ways of seating this group of 5 is 5!×4! ways .

There are 4 boys and 4 girls. In how many ways can they be seated in a row so that all the girls do not sit together?There are 8 persons in total (4 boys + 4 girls)So the number of ways in which 8 persons can be arranged is 8! ways.Let us consider the 4 girls as a single person so there are now 5 persons in total (4 boys + 4 girls as one group or one person). So the number of ways in which 5 persons can be arranged is 5! ways and also the 4 girls can sit among themselves in 4! way so the total number of ways of seating this group of 5 is 5!×4! ways .So the total number of ways in which 4 boys and 4 girls can be seated so that not all the girls sit together is given by= (Total no. of ways in which all 8 can sit)-(No. of ways the group of 5 can sit where the 4 girls all together is taken as a single person)

There are 4 boys and 4 girls. In how many ways can they be seated in a row so that all the girls do not sit together?There are 8 persons in total (4 boys + 4 girls)So the number of ways in which 8 persons can be arranged is 8! ways.Let us consider the 4 girls as a single person so there are now 5 persons in total (4 boys + 4 girls as one group or one person). So the number of ways in which 5 persons can be arranged is 5! ways and also the 4 girls can sit among themselves in 4! way so the total number of ways of seating this group of 5 is 5!×4! ways .So the total number of ways in which 4 boys and 4 girls can be seated so that not all the girls sit together is given by= (Total no. of ways in which all 8 can sit)-(No. of ways the group of 5 can sit where the 4 girls all together is taken as a single person)=> 8! - 5!×4! ways

There are 4 boys and 4 girls. In how many ways can they be seated in a row so that all the girls do not sit together?There are 8 persons in total (4 boys + 4 girls)So the number of ways in which 8 persons can be arranged is 8! ways.Let us consider the 4 girls as a single person so there are now 5 persons in total (4 boys + 4 girls as one group or one person). So the number of ways in which 5 persons can be arranged is 5! ways and also the 4 girls can sit among themselves in 4! way so the total number of ways of seating this group of 5 is 5!×4! ways .So the total number of ways in which 4 boys and 4 girls can be seated so that not all the girls sit together is given by= (Total no. of ways in which all 8 can sit)-(No. of ways the group of 5 can sit where the 4 girls all together is taken as a single person)=> 8! - 5!×4! ways=>37440 ways.

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