Question

There are 5 boys and 5 girls. They sit in a row randomly. What is the chance that all the boys sit together?​

Answer 1

Step-by-step explanation:

The two groups of girls and boys can be arranged in 2! ways 5 girls can be arranged among themselves in 5! Ways. Similarly, 5 boys can be arranged among themselves in 5! ways. Hence, by the fundamental principle of counting, the total number of requisite seating arrangements

= 2!(5! X 5!)

=2!{5!}^{2}