Question

There are 5 consecutive numbers in a list and their average is 23. If the next 5 consecutive numbers are also included in the list, what will be the average of all the ten numbers?

Answer 1

Answer:25.5

Step-by-step explanation:

5X+10=23*5=115

X=105/5=21

10X+45=210+45=255

AVERAGE=255/10=25.5

Answer 2

Answer:139

Step-by-step explanation:

Let the 1st 5 consecutive numbers be (x-3),(x-2),(x-1),x& (x+1).

By question, average of these numbers is 23.

Therefore,

{(x-3)+(x-2)+(x-1)+x+(x+1)}/5=23

Or, 5x-5=5×23

Or, 5(x-1)=5×23

Or, x-1=23

Therefore x=24

Now let the other 5 consecutive numbers be (x+2),(x+3),(x+4),(x+5)&(x+6)

Now the 10 consecutive numbers will be

(x-3)=24-3=21

(x-2)=22

(x-1)=23

x=24

(x+1)=24+1=25

(x+2)=26, (x+3)=27, 28,29 &30

Now the average of these 10 numbers will be

{21+22+23+24+25+26+27+28+29+30}/10

={23+(26+27+28+29+30)/5}

=23+116=139