Question

There are 5 different routes to travel between city A and city B. If the routes are chosen at random, in how many ways one can go from city A and city B and come back to city A? What is the probability that the same route is not taken while returning?

Answer 1

One can go 5*5=25 different ways....the probability that the same route is not taken is 4/5.

Answer 2

There are 5 different routes, so the number of ways you can come and return back will = 25 (5×5 routes) If the same route cannot be taken while coming back without 1 type of route That is why it'll equal to 4/5×25=20