THERE ARE 5 GREEN 7 RED BALLS.TWO BALLS ARE SELECTED ONE BY ONE WITHOUT REPLACEMENT.FIND THE PROBABILITY THAT FIRST IS GREEN AND SECOND IS RED.
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total no of balls = 7+5 =12
no of red balls = 7
no of green balls =5
probability (getting the first ball green )= total no of green balls /total no of balls
5/12
probability (getting the second ball red)=total no of red balls/total no of balls
7/12
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