Math, asked by vt7359515, 10 months ago

. There are 5 Indians , 4 Australians and 3 Russians in a group. If two persons are to be selected at random,

find the probability that,

(a) both are Indians (b) none is Indian (c) at least one is Indian

(d) at most one is Indian

Answers

Answered by ashutoshs1804p9s1e6
1

Answer:

total people=5+4+3=12

a)5/24x100=20.8%

b) 7/24x100=29%

c)5/12x100=41.6%

d)i don't know about this one.

Answered by amitnrw
1

Probability that,  (a) both are Indians = 5/28  , none is Indian = 7/22 ,  at least one is Indian = 15/22 ,  at most one is Indian  = 23/28

Step-by-step explanation:

5 Indians ,

4 Australians and

3 Russians in a group

Total = 5 + 4 + 3 = 12

two persons are to be selected at random

probability that,  both are Indians

= ⁵C₂/ ¹²C₂

= (5/12) * (4/11)

= 20/132

= 5/28

probability that,  none is Indian

=  ⁷C₂/ ¹²C₂

= 7/22

probability that at least one is Indian

= 1 - probability that, none is Indian

= 1 - 7/22

= 15/22

probability that at most one is Indian

=  1  -  probability that both are Indians

= 1  - 5/28

= 23/28

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