There are 5 Indians, 4 chinese and 3 Pakistanis in a round table. Find the
number of ways in which seating arrangements can be made such that
(i) all Indians sit together
(ii) no two Pakistanis sit together.
Answers
Answered by
1
Step-by-step explanation:
1,,,,,its easily solve by first exclude all indian and then sit all chinese and pak..on round table .then put all indian together berween this gap.
7!/3!4!..×8c1×1
Answered by
0
It’s easy
The solution is to make all the Indians sit in together next to next then the 2 Chinese people must sit next to the last Indian in either sides.then two Pakistanis must sit next to both the Chinese then the other two Chinese must sit next to the Pakistanis and the last Pakistani may sit in the middle
The solution is to make all the Indians sit in together next to next then the 2 Chinese people must sit next to the last Indian in either sides.then two Pakistanis must sit next to both the Chinese then the other two Chinese must sit next to the Pakistanis and the last Pakistani may sit in the middle
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