There are 5 letters and 5 envolepe find the number of ways letters can be put in wrong envolope
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If 5 letters has the possibility of 5 envelopes,
(if remains 4 letters and 4 envelops)
if 4 letters has the possibility of 4 envelops
(if remains 3 letters and 3 envelopes)
if 3 letters has the possibility of 3 envelopes
(if remains 2 letters and 2 envelopes)
if 2 letters has the possibility of 2 envelopes
(if remains1 letter and 1 envelope)
if letter has the possibility of 1 envelope
I.e
5×5=25
4×4=16
3×3=9
2×2=4
1×1=1
answer =55
(Or)
5×4×3×2×1=120
5×4×3×2=120
5×4×3=60
5×4=20
5=5
answer =325
I can't understand your question clearly so that's why I'm give two answers
(if remains 4 letters and 4 envelops)
if 4 letters has the possibility of 4 envelops
(if remains 3 letters and 3 envelopes)
if 3 letters has the possibility of 3 envelopes
(if remains 2 letters and 2 envelopes)
if 2 letters has the possibility of 2 envelopes
(if remains1 letter and 1 envelope)
if letter has the possibility of 1 envelope
I.e
5×5=25
4×4=16
3×3=9
2×2=4
1×1=1
answer =55
(Or)
5×4×3×2×1=120
5×4×3×2=120
5×4×3=60
5×4=20
5=5
answer =325
I can't understand your question clearly so that's why I'm give two answers
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