Math, asked by mishete45pdxyp1234, 10 months ago

There are 5 pink, 3 green and 2 yellow balls in a box. Three balls are randomly taken from the box. Then what is the probability that first ball is pink, second is green and third is yellow?​

Answers

Answered by damunadipalli68gmail
0

total picking is equal to 5+2+3=10

p of red ball =5/10=1/2

Answered by pari1918
0

Step-by-step explanation:

Number of pink balls=5

Number of green balls=3

Number of yellow balls= 2

Total no. of balls= 5+3+2

= 10

P ( pink balls) = 5/10

= 1/2

P ( green balls) = 3/10

P ( yellow balls) = 2/10

=1/5

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