Math, asked by ZennyISMyFriend17201, 1 year ago

There are 5 pink, 3 green and 2 yellow balls in box. Three ball are randomly taken from the box. Than what probability first is pink, second is green and third is yellow.

Answers

Answered by destination19
1

the probability of Pinky is 1 by 5 the probability of of green is 1 by 3 the probability of yellow is one by two

Answered by ajayparmar54
0

Step-by-step explanation:

total no. of ball is 10

favourable for pink ball is 5

then

p(E) =favourable outcomes/total outcomes

5/10=1/2

,for green p(X)=3/10

and for yellow p(X)=2/10

=1/5

ans.

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