English, asked by avu59, 5 months ago

There are 5 pipes working in tandem which can fill a tank of 1,800 litre capacity in 40 minutes. Out of
these 5 pipes, 3 are used to fill liquid in the tank. Each of these 3 pipes can individually fill the tank at
the rate of 30 litre/min, 45 litre/min and 15 litre/min respectively. The other two pipes are used to
empty the tank - one of which can empty it at the rate of 30 litre/min. What is the rate (litre/min) at
which the other pipe alone can empty the tank, considering that the tank is full?​

Answers

Answered by amitnrw
12

Given : 5 pipes working in tandem which can fill a tank of 1,800 litre capacity in 40 minutes. Out of these 5 pipes, 3 are used to fill liquid in the tank. Each of these 3 pipes can individually fill the tank at the rate of 30 litre/min, 45 litre/min and 15 litre/min respectively. The other two pipes are used to empty the tank - one of which can empty it at the rate of 30 litre/min.

To Find :  Rate at which other pipe empty tank

alone can empty the tank, considering that the tank is full?​

Solution:

Pipe 1  30 Litre / min can fill in 40  minutes = 30 * 40 = 1200 litres

Pipe 2  45 Litre / min can fill in 40  minutes = 45 * 40 = 1800 litres

Pipe 3  15 Litre / min can fill in 40  minutes = 15 * 40 = 600 litres

Pipe 4 30 litre/min.  can empty  in 40 minutes = 30 * 40 = 1200 litres

Pipe 5 x litre/min.  can empty  in 40 minutes = x * 40 = 40x litres

1200 + 1800 + 600 - 1200 - 40x  = 1800

=> 40x  = 600

=> x = 15

rate (litre/min)   pipe can empty tank = 15 litre /min

Time alone = 1800/15  = 120 mins = 2 hrs

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