Question

There are 5 Red 2 yellow and 3 white Roses in a flower pot. Select one rows from it at random .What is the probability that the selected rows is of
1. Yellow
2. Not yellow
​

Answer 1

Given

$\bold{Total \ no: \ of \ red \ roses} = 5$

$\bold{Total \ no: \ of \ yellow \ roses} = 2$

$\bold{Total \ no: \ of \ white \ roses} = 3$

$\bold{Total \ no: \ of \ roses} = 5+2+3=10$

SOMETHING YOU NEED TO KNOW

$\boxed{\bold{Probability \ of \ an \ outcome = \dfrac{Given \ outcome}{Total \ no: \ of \ outcomes}}}}}}}}$

1) Probability of a yellow rose

$\bold {Probability \ of \ a \ yellow \ rose = \dfrac{Total \ no: \ of \ yellow \ roses}{Total \ no: \ of \ roses}}$

$\implies \dfrac{2}{10}$

$\implies \boxed{\boxed{\bold{\frac{1}{5}}}}}}}}}}$

2) Probability of not getting a yellow rose

$\bold {Probability \ of \ not \ getting \ a \ yellow \ rose =1-\dfrac{Total \ no: \ of \ yellow \ roses}{Total \ no: \ of \ roses}}$

$\implies 1 - \dfrac{1}{5}$

$\implies \dfrac{5-1}{5}$

$\implies \boxed{\boxed{\bold{\frac{4}{5}}}}}}}}}}$

                                                                         

Answer 2

$\huge \underline{ \blue{ \boxed{ \bf \red{Answer:-}}}}$

Total number of roses in the flower pot = 5+3+2

= 10

∴ Number of possible outcomes to select a rose at random is 10.

(i) Let 'A' be the event that the selected rose is of yellow colour.

No. of yellow roses in the flower pot = 2

∴P(A) = \frac{2}{10} = 0.2

(ii) Let A be the event when the selected rose is yellow in colour.

Then, C is the event when the selected rose is not of yellow colour.

No. of yellow roses in the flower pot = 2

∴ P(A) = \frac{2}{10} = 0.2

Now, P(C) = 1 –P(A) = 1 – 0.2 = 0.8

$\bf\blue{Hope\ it\ helps.}$$\bf\pink{Plz\ Mark\ As\ Brainliest.}$