there are 5 red 6 black and 7 white balls in a bag A ball is drawn at random from the bag find the probability that it may be number 1) a red ball number 2) not a white ball
Answers
Answer:1) 5/18
2)11/18
Step-by-step explanation:
Given,
- Number of red balls = 5
- Number of black balls = 6
- Number of white balls = 7
To find,
We have to find the probability of getting
- a red ball number
- not a white ball
Solution,
The probability that a ball is drawn at random from the bag is a red ball is 5/18 and not a white ball is 11/18.
Total number of balls = 18
Number of red balls = 5
Number of black balls = 6
Number of white balls = 7
Probability = favorable cases / Total number of cases
P( of getting a red ball number) = number of red balls / Total number of balls
P( of getting a red ball number) = 5/18
P( not a white ball) = P( red ball) + P(black ball)
= 5/18 + 6/18
P( not a white ball) = 11/18
Hence, the probability that a ball is drawn at random from the bag is a red ball is 5/18 and not a white ball is 11/18.