Question

There are 5 red and 3 green pens in a bag. There
are 2 red and 6 green pens in another bag. A pen
is picked up at random from one bag. Using the
following instructions, find the probability that
the pen picked up :​

Answer 1

In bag 1

P(r) = 5/8

P(g) = 3/8

In bag 2

P(r) = 2/8 = 1/4

P(g) = 6/8 = 3/4

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Answer 2

The probability of the pen picked up from Bag 1 to be red is 5/16, to be green is 3/16 while the respective probabilities from Bag 2 are 2/16 and 6/16.

• Since ball is picked at random from one of the bag so the probability of each bag is 1/2
• Hence the probability of the pen picked up = probability of pen if there was only one bag multiplied by the probability of each bag

The probabilities of pens in the respective bags are as follows:-

Bag 1

• P(r)=5/8
• P(g)=3/8

Bag 2

• P(r)=2/8
• P(r)=6/8