There are 5 tickets in a box and number 1, 1, 2, 2 and 3 are
written on tickets. Two tickets are taken at random from the box.
Find the expected value of the sum of the numbers on the tickets.
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Answer:
Probability of sum as 2=
C
2
5
C
2
2
=
10
1
Probability of sum as 3=
C
2
5
C
1
2
×C
1
2
=
10
6
Probability of sum as 4=
C
2
5
C
2
3
=
10
3
xpxp
21/102/10
36/1018/10
43/1012/10
Exceptationofsum=∑xp
=
10
2
+
10
18
+
10
12
=
10
32
=3.2
Step-by-step explanation:
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