Question

There are 5 white balls and 3 black balls in one urn ; 4 white and 8 black balls in second urn and 3 white and 6 black balls in the third urn. A ball is taken at random from the first urn and is placed in the second urn.Then a ball is taken from the second urn and it is placed in the third urn.Now a ball is taken from the third urn.Find the probability that the third selected ball is white... Please provide me with the solution ....

Answer 1

We know that the third urn has three white and six black balls and the ball taken from the second urn. Therefore in total, the third urn has ten balls. P(white ball)=3/10