Question

There are 50 bulls
There are 9 pillars
Those 50 bulls should be tied to these 9 pillars ...
Double digits should not be on any pillar ...
Only one number should appear on each pillar ...

Answer 1

Answer:

How can 50 cows be tied on 9 pillars with an odd number on each pillar?

Just divide 50 cows in 9 groups, you have 50/9=5.5555555555……. (do not round up). So you essentially have an “odd” number (in fact, lots of them) at each digit, on each pillar. This task will definitely qualify for gross animal cruelty.

Otherwise, your answer will be the number of solutions of the equation ∑9i=1xi=50 where xi=2n−1 , n∈N. This equation is not solvable .

So, you have to utilize some tricks to solve this problem, like tying one or more cows to more than 1 pillar. This can be solved in a number of ways, one of which is mentioned by . Another solution could be:

P1 to P6=> 7 cows each=42 cows

P7 => 3 cows

P8 & P9=> 2 cows each + one common cow shared by both = 5 cows

Cows are best left free than on a leash

Step-by-step explanation:

please mark my ans as brainliest please

Answer 2

Step-by-step explanation:

for each pillar 5 bulbs must be tied.

then 5 will be remained.

if we tie the remain 5 to alternate odd pillars, every bulb is tied to pillars