Question

there are 50 mangoes 20 of which are unripe another basket contains 40mangoes and 15 unripe if we take one mangoes each basket
find the probability of getting both are right ?
find the probability of getting both are unripe
find the probability of one ripe and one unripe
find the probability of atleast on ripe
find the probability of atleast one unripe​

Answer 1

Answer:

50-20=30

40-15=25

30+25=55

this is the solution mark me as brainliest and this is the correct way

Answer 2

Step-by-step explanation:

Let there be x mangoes in the basket.

From given information, we can infer that x when divided by 2, 3, 4, 5 or 6 leaves a remainder -1 & is a multiple of 7.

Firstly, let's find the LCM of 2, 3, 4, 5 & 6 which comes out to be 60.

Now, x = 60n - 1 where n is a whole number.

We have:

(60n-1)mod7=0.

(4n-1)mod7=0 as 60mod7=4.

Here, least possible value of n is 2.

x =-60(2)-1=120-1=119.

There are 119 mangoes in the basket.