Question

There are 500 children in a school. For a P.T. drill they have to stand in such a manner that the number of rows is equal to number of columns. How many children would be left out in this arrangement.
I want the answer fast ​

Answer 1

Answer:

hey mate!! here is your solution

Hope it helps you!!!

Answer 2

$\tt \red{Answer:-}$

Let the no of row and column be x.

Total number of row and column= x×x= x²

$\tt{ {x}^{2} = 500}$

$\implies \tt{x = \sqrt{500} }$

$\implies \tt{x = 22.36}$

So, Number of rows=Numbers of column= 22

So, No. of children= 22*22= 484

Therefore, no. of children would be left out in this arrangement= 500-484= 16

Hence, 16 children would be left out in this arrangement.