Question

There are 527 apples, 646 pears
and 748 arge oranges. These are
to be arranged in heaps containing
the same number of fruits. Fine the greatest number of fruits possible in each heap . How many heaps are formed please solve step by step please solve fast who send me answer I join him in brainlist​ please answer step by step​

Answer 1

Answer:

17 heaps were formed, each containing 31 apples, 38 pears, and 44 oranges.

So, in total 17 heaps had 113 fruits each.

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Step-by-step explanation:

No. of heaps = H.C.F. of the number of fruits.

Prime Factorization(P.F.) method to find H.C.F.

=> P.F. of 527=17*31

=> P.F. of 646=2*17*19

=> P.F. of  748=2*2*11*17

>> Common factor = 17

∴ H.C.F. = 17

So, 17 heaps are possible to be made.

∴ No. of Apples in each heap = $\frac{527}{17}$ = 31

∴ No. of Pears in each heap = $\frac{646}{17}$ = 38

∴ No. of Oranges in each heap = $\frac{748}{17}$ = 44

Hence, in total 17 heaps were formed.

Each heap had 31 apples, 38 pears, and 44 oranges.

So, each heap had 31+38+44 = 113 fruits in total.

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