Question

there are 527 pencils,646 erasers and 748 sharpners.these are to be arranged in packets containing the same number of items.find the greatest number of items possible in each packet.how many packets are formed​

Answer 1

Tofindthemaximumnumberofitemspossibleineachpacket,weneedtofindtheGreatestCommonFactorof527Pencils,646erasersand748sharpeners.WeneedtolisttheFactorsofeachnumberasgivenbelowandidentifythegreatestcommonfactor.

\begin{lgathered}The \; factors \; of \; 527 \; are:\\1, \; 17, \; 31, \; 527\\\\The \; factors \; of \; 646 \; are:\\1, \; 2, \; 17, \; 19, \; 34, \; 38, \; 323, \; 646\\\\The \; factors \; of \; 748 \; are:\\1, \; 2, \; 4, \; 11, \; 17, \; 22, \; 34, \; 44, \; 68, \; 187, \; 374, \; 748\\\\Then \; the \; greatest \; common \; factor \; is \; 17.\end{lgathered}Thefactorsof527are:1,17,31,527Thefactorsof646are:1,2,17,19,34,38,323,646Thefactorsof748are:1,2,4,11,17,22,34,44,68,187,374,748Thenthegreatestcommonfactoris17.

\begin{lgathered}Conclusion: \\There \; will \; 31 \; Pencils, \; 38 \; Erasers,\\ \; and \; 44 \; Sharpeners \; in \; each \; of \; SEVENTEEN \; packet.\end{lgathered}Conclusion:Therewill31Pencils,38Erasers,and44SharpenersineachofSEVENTEENpacket.

Answer 2

calculate the pencil, eraser, sharpner is 1921. this is solution