Math, asked by devil93k, 1 year ago

There are 576 boys and 448 girls in a school that are to be divided into equal sections of either boys or girls alone. Find the total numbers of sections thus formed plzzz solve 5th qou

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Answered by KshitijBhardwaj
345
DUDE THE ANSWER IS 16. LET'T SEE HOW
TAKE HCF OF 576 AND 448=64
NOW DIVIDE:576/64=9
448/64=7
ADDING THE QOUTIENTD TOGETHER, WE GET:9+7=16
THUS, REQUIRED ANSWER IS 16.
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Answered by aquialaska
184

Answer:

The total numbers of sections are 16.

Step-by-step explanation:

Given:

Number of boys in school = 576

Number of girls in school = 448

To find: Total Number of sections such that each section has either boys or girls.

Height Common Factor ( HCF ) of both number gives the number of students in a section.

HCF of 576 and 448

576 = 2 ×  2 × 2 × 2 × 2 × 2 × 3 × 3

448 = 2 ×  2 × 2 × 2 × 2 × 2 × 7

HCF = 2 ×  2 × 2 × 2 × 2 × 2 = 64

Number of sections of Boys = 576/64 = 9

Number of sections of girls  448/64 = 7

Total Number of sections = 9 + 7 = 16

Therefore, The total numbers of sections are 16.

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