There are 6*10¹⁹ electrons per unit cubic metre of pure semiconductor. What will be the number of holes for this semiconductor of dimension 1 cm*1 cm*2 cm? [Ans: 12*10¹³ ]
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Dear Student,
◆ Answer -
Nh = 1.2×10^14 holes
◆ Explaination -
No of electrons in the semiconductor is -
Ne = 1×10^-2 × 1×10^-2 × 2×10^-2 × 6×10^19
Ne = 1.2×10^14 e-
We know that no of holes is equal to no of electrons, thus no of holes in semiconductor is 1.2×10^14. i.e. Nh = 1.2×10^14 holes.
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