Question

There are 6 boys who enter a boat with 8 seats, 4 on each side. In how many ways can they sit anywhere on the boat?

Answer 1

Answer:

choose any 6 seats from 8 and rearrange

$\binom{8}{6} \times 6!$

Answer 2

Number of ways are  $\bold {^8P_6}$= 20160

Step-by-step explanation:

In this question we have to arrange 6 boys such that there are 8 seats,4 on each side.

Number of ways are = $^8P_6$

                                   =$\frac{n!}{(n-r)!}$

                                  =$\frac{8!}{(8-6)!}$

                                   = $\frac{8!}{2!}$

                                   = $\frac{8\times 7\times 6\times 5\times 4\times 3\times 2\times 1}{2\times 1}$

                = 8×7×6×5×4×3

                 = 20160