there are 6 clips in a box and number 1 ,1,2,2,3,3 are written on these.two sleep are taken at random from the box.the expected value of the sum of numbers on two slips
Answers
Step-by-step explanation:
Answer by Fombitz(32378) (Show Source): You can put this solution on YOUR website!
Look at all of the possible outcomes, 30 of them,
(1,1)(1,2)(1,2)(1,3)(1,3)
(1,1)(1,2)(1,2)(1,3)(1,3)
(2,1)(2,1)(2,2)(2,3)(2,3)
(2,1)(2,1)(2,2)(2,3)(2,3)
(3,1)(3,1)(3,2)(3,2)(3,3)
(3,1)(3,1)(3,2)(3,2)(3,3)
and their sums,
2,3,3,4,4
2,3,3,4,4
3,3,4,5,5
3,3,4,5,5
4,4,5,5,6
4,4,5,5,6
So then look at the frequency of each sum,
2:2
3:8
4:10
5:8
6:2
Then the probabilities would be,
2:2%2F30=1%2F15
3:8%2F30=4%2F15
4:10%2F30=1%2F3
5:8%2F30=4%2F15
6:2%2F30=1%2F15
So,
E=2%281%2F15%29%2B3%284%2F15%29%2B4%281%2F3%29%2B5%284%2F15%29%2B6%281%2F15%29
E=2%2F15%2B12%2F15%2B20%2F15%2B20%2F15%2B6%2F15
E=60%2F15
E=4
Answer:
4
Step-by-step explanation:
Look at all of the possible outcomes, 15 of them,
(1,1)(1,2)(1,2)(1,3)(1,3)
(2,1)(2,1)(2,2)(2,3)(2,3)
(3,1)(3,1)(3,2)(3,2)(3,3)
and their sums,
2,3,3,4,4
3,3,4,5,5
4,4,5,5,6
So then look at the frequency of each sum,
2 appears once
3 appears 4 times
4 appears 5 times
5 appears 4 times
6 appears once
Then the probabilities would be,
2→ 1/15
3→ 4/15
4→ 5/15
5→ 4/15
6→ 1/15
Expected value: 2(1/15) + 3(4/15) + 4(5/15) + 5(4/15) + 6(1/15)
= 2/15+12/15+20/15+20/15+6/15
= 60/15
= 4
I hope it helps