Question

There are 6 letters L1 L2 L3 l4 L5 L6 and their corresponding 6 envelopes E1 E2 E3 E4 E5 E6 letters having odd value can be put into odd value and blocks and even value letters can be put into even value envelope so that no letter go into the right and develops then number of arrangements equal

Answer 1

Answer:

Step-by-step explanation:

L1 , L3 , L5

can be put in E1 , E3  , E5

ist Letter can be put in 3 envelopes

then second letter can be put in two envelopes

& thirs letter in remaining one envelope

so Total number of ways = 3 * 2 = 6

Similarly

L2 , L4 , L6

can be put in E2 , E4  , E4

in  6 Ways

total ways = 6 * 6  = 36

and there is only one correct way

Hence 35 Ways it can go in wrong

if Question is no letter go into the right

=> L1 can go in 2 ways  E3 or E5

Case 1  : L1 go in  E3   then  L3 can go in E5  & L5 in L1  ( as L5 can not go into E5)

Case 2 :  L1 go in  E5   then  L3 can go in E1  & L5 in L3  ( as L3 can not go into E3)

so total 2 cases Where no Letter goes into right envelope

Similalry 2 cases for  L2 , L4 , L6 can be put in E2 , E4  , E4

in 2 Ways which has no right

hence 2 * 2 = 4 Ways

Total 4 Ways