Question

There are 6 marbles in a box. 2 Red, 3 Green and 1 Blue. What is the probability of drawing a non-red marble ?​

Answer 1

Answer:

Total number of marbles = 6

So n(s) = 6

Number of marbles marked with 2 = 1

n(e) = 1

Probability = \frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ outcomes}\

=\ \frac{n\left(e\right)}{n\left(s\right)}\ =\ \frac{1}{6}

ii) Total number of marbles = 6

n(s) = 6

Number of marbles marked 5 = 1

n(e) = 1

Probability = \frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ outcomes}\

=\ \frac{n\left(e\right)}{n\left(s\right)}\ =\ \frac{1}{6}

Answer 2

Answer:

Given: Marbles with numbers marked on each of them are 1,2,3,4,5 and 6.

∴ Probability of drawing marble with number 5 =  total favorable outcome/sample space  

​ ∴ Probability of getting number 5 = 1/ 6  

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