There are 6 marbles in a box with numbers from 1 to 6 marked on each of them.What is the probability of drawing a marble with number 4?
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Answer:
Solution:
Total number of marbles = 6
So n(s) = 6
Number of marbles marked with 2 = 1
n(e) = 1
Probability = \frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ outcomes}\
Total number of outcomes
Number of favourable outcomes
=\ \frac{n\left(e\right)}{n\left(s\right)}\ =\ \frac{1}{6}=
n(s)
n(e)
=
6
1
ii) Total number of marbles = 6
n(s) = 6
Number of marbles marked 5 = 1
n(e) = 1
Probability = \frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ outcomes}\
Total number of outcomes
Number of favourable outcomes
=\ \frac{n\left(e\right)}{n\left(s\right)}\ =\ \frac{1}{6}=
n(s)
n(e)
=
6
1
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