Question

there are 6 multiple choice questions in an exam. how many sequence of answers are possible if the first three questions have 3 choices each and the remaining three have 4 choices each?​

Answer 1

we know

there are 6questions and

three questions with three choices each

3 × 3 = 9

and for the last the last three questions there are four choices

so there will be 4×3=12

So 49 + 12 is equal to 21 choices