Question

There are 6 red balls , 4 blue balls and 5 green balls in a bag. Virat is taking
out one ball from the bag. Find the probability of getting (a) a green ball (b) a non – green ball

Answer 1

Answer:

Total ball= 6+4+5= 15

P( green ball)= 5/15= 1/3

Total ball rather than green ball= 6+4= 10

P( non green ball)= 10/15