Question

there are 6 slips in a box and no's 1,1,2,2,3,3 are written on these slips.two slips are taken at random from the box,find the expected value of the sum of the no's on the two slips

Answer 1

The expected values are 2,3,4,5,6.
But the mojar probability is of 4 as it has two cases (2+2) & (1+3) while all the other sums have only one way to get.

Answer 2

Answer:

4

Step-by-step explanation:

Look at all of the possible outcomes, 15 of them,

(1,1)(1,2)(1,2)(1,3)(1,3)

(2,1)(2,1)(2,2)(2,3)(2,3)

(3,1)(3,1)(3,2)(3,2)(3,3)

and their sums,

2,3,3,4,4

3,3,4,5,5

4,4,5,5,6

So then look at the frequency of each sum,

2 appears once

3 appears 4 times

4 appears 5 times

5 appears 4 times

6 appears once

Then the probabilities would be,

2→ 1/15

3→ 4/15

4→ 5/15

5→ 4/15

6→ 1/15

Expected value: 2(1/15) + 3(4/15) + 4(5/15) + 5(4/15) + 6(1/15)

= 2/15+12/15+20/15+20/15+6/15

= 60/15

= 4

I hope it helps