There are 6 soccer teams A, B, C, D, E and F in the soccer league game. All the 6 teams play each Saturday during the season. Each team
must play against each of the other teams once and only once during the seasons. (1) Team A plays against team D 1st and team F 2nd
(ii) Team B plays against team E 1st and team C 3rd (ili) Team C plays against team F1st If D wins 5 games, which of the following must
be true?
O loses 5 games
O A wins 4 games
O A wins its first game
OB loses at least 1 game
Answers
Answer:
option a is the correct answer
The correct option for the reasoning is that "B loses at least 1 game."
Given:
There are 6 teams in the league.
Each team plays the other team only once.
To find:
The correct option among the given statements which adequately supports the given logic.
Solution:
Out of the 6 teams each team will play only 5 soccer matches in each season.
It is given that they play each team only once.
Hence team D will play five matches such as DA , DB, DC , DE and DF only, or 5 matches.
Now it is given that D will win 5 matches , therefore logic dictates that the match between D and B is won by D.
Hence B loses 1 match at least.
Therefore from all the given data we can say that only the option "B loses at least 1 match" .
The other options are not valid because:
1) A could lose 5 games but we don not have enough information .
2)A wins 4 games , again not enough information.
3) A definitely did not win his first match as D won that match
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