There are 60 office suites company A has 1/3 Company B has 2/5 how many does Company C have
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A has = 1/3 ×60 = 20
B has 2/5 ×60 = 24
then
C have = 1-(1/3+2/5)= 1-(5+6)/15 = 1-11/15 = 4/15
hence C have 4/15 of suits = 4/15 ×60 = 16
C have 16 suits.
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