Question

There are 60 pebbles and 2 persons a and

b. a tables 1 pebble, b takes 2 pebbles and again a takes 3 pebbles and b takes 4 pebbles and this goes on alternatively. who takes the maximum number of pebbles?

Answer 1

In this scenario,

A takes the first turn;

Therefore, after 5 turns, A will be at : 1+3+5+7+9=25;

Similarly, when it’s B’s turn;

after 5 turns B will be at: 2+4+6+8+10=30;

Now, when it’s A’s turn again, A has to take 11 pebbles but as there are only 5 available, A will take 5;

60-(25+30) = 5;

So, both A and B have 30 pebbles each at the end.