There are 60 students in a class among which 30 are
boys. In another class there are 50 students among
which 25 of them are boys. If one from each class is
selected,
(a) What is the probability of both being girls ?
(b) What is the probability of having atleast one girl?
Answers
1/4 is Probability of both being girls & 3/4 is probability of having atleast one girl
Step-by-step explanation:
Class 1 -
Total Students = 60
Boys = 30
Girls = 60 - 30 = 30
Class 2 -
Total Students = 50
Boys = 25
Girls = 50 - 25 = 25
One from each class is selected,
Probability of both being girls = (30/60)(25/50)
= (1/2)(1/2)
= 1/4
probability of having atleast one girl = 1 - Probability of both Boys
= 1 - (30/60)(25/50)
= 1 - (1/2)(1/2)
= 1 - 1/4
= 3/4
Learn more:
if two dice are tossed, find the probability of throwing a total of 10 or ...
https://brainly.in/question/7714685
There are 5 Indians , 4 Australians and 3 Russians in a group. If two ...
https://brainly.in/question/13377423
Answer: a) 1/4
b) 3/4
Step-by-step explanation:
Class 1 -
Total Students = 60
Boys = 30
Girls = 60 - 30 = 30
Class 2 -
Total Students = 50
Boys = 25
Girls = 50 - 25 = 25
One from each class is selected,
Probability of both being girls = (30/60)(25/50)
= (1/2)(1/2)
= 1/4
probability of having atleast one girl = 1 - Probability of both Boys. (Since p(E)= 1 - p(NOT, E ,) )
= 1 - (30/60)(25/50)
= 1 - (1/2)(1/2)
= 1 - 1/4
= 3/4