There are 60 sweets in a jar. The first person took one sweet, and each consecutive person took more sweets than the person before, until the jar was empty. What is the largest number of people that could have eaten sweets from the jar?
Answers
Answer:Here,
first took 1 then second person took 2
then
60×3=20
answer 20 people's took sweets
Step-by-step explanation:
Answer:
10 is the largest number of people that could have eaten sweets from the jar.
Step-by-step explanation:
The first person took one sweet.
Let us assume that the second person took 2, third person took 3, and so on.
This follows an arithmetic sequence (natural numbers).
The sum of first ten natural numbers = 55
If the persons took sweets in the assumed order, then there will be 5 sweets remaining. It could not be given to a 11th person as it is less than 10. So, it is better to assume that that 5 sweets were taken by the 10th person itself.
Thus the number of sweets taken by the people in the order is:
1, 2, 3, 4, 5, 6, 7, 8, 9, 15
This satisfies the mentioned condition that each consecutive person took more sweets than the person before.
Thus the largest number of people that could have eaten sweets from the jar = 10.
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