Question

there are 60 terms in an AP of which the first term is 8 and the last term is 185. the 31 term is

Answer 1

here
a=8,
l=tn=185,
n=60,

then

t31=???,

185=8+(60-1)×d,

185-8=59×d,

177/59 =d,

then

d=177/59,

d=3,


hence

t31 =8+(31-1)×3,

t31=8+30×3,

t31=8+90,

then

t31=98

Answer 2

We are given: a=8 a60 = 185 => a60 = a+(n-1)d   185     = 8 + 59d       177  = 59d         3 = D NOW, a31 = 8 + 30 × 3                   = 98